Question

If fmax and fmin are the maximum and minimum forces respectively acting on a body of cross section area a, then the value of the alternating stress experienced by the body is

a.(fmax+fmin)/2a,

b.(fmax+fmin)/a

c.(fmax-fmin)/2a

d.(fmax-fmin)/a

Answer 1

Answer:

C.$Alternating\ stress=\dfrac{F _{max}-F_{min}}{2A}$

Explanation:

Given that

Maximum force= fmax

Minimum force = fmin

Area =a

We know that stress is the ratio of force and area.

Alternating  stress

$Alternating\ stress=\dfrac{\sigma _{max}-\sigma_{min}}{2}$

$\sigma _{max}=\dfrac{F_{max}}{A}$

$\sigma _{min}=\dfrac{F_{min}}{A}$

So from above we can say that

$Alternating\ stress=\dfrac{\sigma _{max}-\sigma_{min}}{2}$

$Alternating\ stress=\dfrac{F _{max}-F_{min}}{2A}$

So option C is right.