Question

if for a GP r=1/3,a =9 then find t,7​

Answer 1

Answer:

7th term = 1/81

Step-by-step explanation:

a = 9 r = 1/3

$7th \: term \: = a {r}^{7 - 1} \\ = 9 \times { (\frac{1}{3} )}^{6} \\ = 9 \times \frac{1}{ {3}^{6} } \\ = \frac{ {3}^{2} }{ {3}^{6} } \\ = {3}^{2} \times {3}^{ - 6} \\ = {3}^{2 - 6} \\ = {3}^{ - 4} \\ = \frac{1}{ {3}^{4} } \\ = \frac{1}{81}$

hope you get your answer