X varies inversely as square of y. Given that y = 2 for x = 1. The value of x for y = 6 will be equal to
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Answered by
10
Given x is inversely prop as the sq. of y.so if we take k as constant of variation then,
x=k*1/y^2
now putting the initial values of x and y we get,
4=k*1/9 or k =36
so the law of variation becomes x=36*1/y^2
now putting the value of y=6 in this equation we get,
x=36*1/6^2 or x=36*1/36=1
so,x=1 when y=6.
x=k*1/y^2
now putting the initial values of x and y we get,
4=k*1/9 or k =36
so the law of variation becomes x=36*1/y^2
now putting the value of y=6 in this equation we get,
x=36*1/6^2 or x=36*1/36=1
so,x=1 when y=6.
Answered by
1
Answer:
1/6
Step-by-step explanation:
x varies inversely as square of y,
x=k×1/y²
Now, put the initial values of x and y,
4=k×1/9
k=36
So, the law of variation becomes
x=36×1/y²
Now, put the value of y=6
x=36×1/6²
x=36×1/6×6
( cancel 6×6 and 36)
x= 1
y= 6
HOPE IT IS HELPFUL!!!!!!
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