Math, asked by jagdishjambe3853, 1 year ago

X varies inversely as square of y. Given that y = 2 for x = 1. The value of x for y = 6 will be equal to

Answers

Answered by Anonymous
10
Given x is inversely prop as the sq. of y.so if we take k as constant of variation then,

x=k*1/y^2

now putting the initial values of x and y we get,

4=k*1/9 or k =36

so the law of variation becomes x=36*1/y^2

now putting the value of y=6 in this equation we get,

x=36*1/6^2 or x=36*1/36=1

so,x=1 when y=6.
Answered by mamatabehera5652
1

Answer:

1/6

Step-by-step explanation:

x varies inversely as square of y,

x=k×1/y²

Now, put the initial values of x and y,

4=k×1/9

k=36

So, the law of variation becomes

x=36×1/y²

Now, put the value of y=6

x=36×1/6²

x=36×1/6×6

( cancel 6×6 and 36)

x= 1

y= 6

HOPE IT IS HELPFUL!!!!!!

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