Math, asked by sigiyam, 1 year ago

If for an A. P., t10=25, t18=45, what is the value of t14? ​

Answers

Answered by gaya3123
13

Answer:

65

Step-by-step explanation:

T10=25

T18=45

We know that

an =a+(n-1) d

25=a(10-1)d

25=a+9d -----(1)

45=a(18-1)d

45=a+17d------(2)

substitute (2) in (1)

45= a+17d

25=a+9d

-----------------------

20= 8d

d= 20/8

d= 2.5

putting the value of d in equation (1)

25=a+9*2.5

25=a+22.5

a=25-22.5

a=2.5

Now we have

a=2.5. d=2.5

T14=a+(n-1)d

T14= 2.5+(14-1)2

= 2.5+13(2)

= 2.5 x 26

=65

Answered by mikun24
7

Answer:

Hy mate

your answer is 65

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