If for an A. P., t10=25, t18=45, what is the value of t14?
Answers
Answered by
13
Answer:
65
Step-by-step explanation:
T10=25
T18=45
We know that
an =a+(n-1) d
25=a(10-1)d
25=a+9d -----(1)
45=a(18-1)d
45=a+17d------(2)
substitute (2) in (1)
45= a+17d
25=a+9d
-----------------------
20= 8d
d= 20/8
d= 2.5
putting the value of d in equation (1)
25=a+9*2.5
25=a+22.5
a=25-22.5
a=2.5
Now we have
a=2.5. d=2.5
T14=a+(n-1)d
T14= 2.5+(14-1)2
= 2.5+13(2)
= 2.5 x 26
=65
Answered by
7
Answer:
Hy mate
your answer is 65
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