if force f=(4i+jcap)n velocity v=(2i+jcap)m/s power is 19 watt then what is the value of x
Answers
if force f=(4i+jcap)n velocity v=(2i+jcap)m/s power is 19 watt then what is the value of x
Velocity v along +Z axis does not feel any experience (B is on the -k direction means -Z axis)
Explanation:
When a proton has a velocity of V=(2i+3j)x10^6 m/s and also it experiences a force of F=-1.28 x 10^-13 kN then we can say that the direction of B is in the -k direction because the V makes non-zero force which is the component of j vector. Component j gives -k vector for positively charged particle. In this case it is the proton.
Now the magnitude of v is √13x10^6m/sec
F =-1.28x10^-13 kN (Given)
We know a charge of a particle is q = 1.6 x
From the Lorentz force equation we get,
B = F/qv = 1.28x10^-13 N /(1.6 x 10^-19 C)(3.6 x 10^3)
B = -0.222 x 10^3=-222 in -k direction
If i corresponds to the +x-axis
, j to the +y-axis and k to the +z-axis then -k corresponding to -Z direction. Then velocity v along +Z axis does not feel any experience (B is on the -k direction means -Z axis)