Question

if force is doubled and the area of contact is halved then what is the pressure exerted?

Answer 1

pressure=force/area

p=2F/A/2

p=4[F/A]

final pressure=4[initial pressure]

Answer 2

$\red{HEY\:BUDDY!!}$

HERE'S THE ANSWER...

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♠️ Pressure is known as force ( F ) per unit area ( A ), i.e

=> Pressure = Force / Area

=> P = F / A

⏺️ If Force is doubled and area is halved the new pressure ( P' ) is

=> P' = ( 2 × F ) / ( A / 2 )

=> P' = 2 ( 2 × F ) / A

=> P' = 4 ( F / A )

⏺️ We can write ( F/A ) = P

=> $\boxed{ P'\:= \: 4 \: ( F \ A)}$

♠️ So new pressure ( P' ) will be 4 time of initial pressure ( P ) .

HOPE HELPED...

$\red{JAI \:HIND..}$

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