Question

if force on one charge of a dipole due to the second is 0.2N towards right what is the force on the second charge due to the first and in which direction​

Answer 1

Answer:

Let's first consider a dipole consisting of 2 equal charges placed at small distance from each other.

So According to Electrostatics Force Theorem , the magnitude of force will be :

$F = \dfrac{1}{4\pi \epsilon_{0}} \dfrac{ {q}^{2} }{ {d}^{2} }$

As per the question , we see :

$F = \dfrac{1}{4\pi \epsilon_{0}} \dfrac{ {q}^{2} }{ {d}^{2} } = 0.2 \: N$

Now , it has also been mentioned that : Force of one charge on the dipole due to the other charge is directed rightwards.

This is possible only in 1 case :

Positive charge on left side and negative charge on right side .

Let the positive charge experience 0.2 N force rightwards due to Negative .

Similarly the negative charge will also experience 0.2 N charge towards the right side.

Refer to the attached diagram.

Answer 2

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QUESTION :

if force on one charge of a dipole due to the second is 0.2N towards right what is the force on the second charge due to the first and in which direction......

SOLUTION :

FORMULAE USED :

F = { 1 } / { 4 π e 0 } × { q ^ 2 / d^ 2 }

Given Force :

if force on one charge of a dipole due to the second is 0.2N towards right.

See the attachment..

Left side Is + ve and right side - ve.

Now, the same force is exerted on the other diapole.

The direction is also the same .