Question

If four angles of a cyclic quadrilateral are (2x –1)º, (y + 5) ; (2y + 15)º and (4x – 7)º, then​

Answer 1

Answer:

Given that ;

Four angles of a Cyclic Quadrilateral ;

First Angle = ( 2x - 1 )°

Second Angle = ( y + 5 )°

Third Angle = ( 2y + 15 )°

Fourth Angle = ( 4x - 7 )°

We Know That ;

Sum of the angles of a Quadrilateral = 360°

( 2x - 1 )° + ( y + 5 )° + ( 2y + 15 )° + ( 4x - 7 )° = 360°

6x - 1 + 3y + 5 + 15 - 7 = 360°

6x + 3y + 12 = 360°

6x + 3y = 360 - 12

6x + 3y = 348°