Question

if four horizontal forces F1=3N F2=6N F3=3N AND F4=6N is applied on a body of mass 5 kg. If force F3 is removed ,then find the value of rate of change of momentum.

Answer 1

The particle remains stationary on the application of three forces that means the resultant force is 0.

This implies

F1 = - (F2 + F3)

Since, if the force F1 is removed, the forces acting are F2 and F3, the resultant of which has the magnitude of F1.

Therefore, the acceleration of the particle is F1/m