if four points A(6,3),B(-3,5),C(4,-2) and D(x,3x) are given in such a way that area of triangle DBC/ area of triangle ABC = 1/2 , find the value of x.
Prachidwivedi:
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We know that,
If three vertices are given in a quadrilateral then the fourth vertex is (x1+x3-x2,y1+y3-y2).
Let,
A(6,3)=(x1,y1)
B(-3,5)=(x2,y2)
C(4,-2)=(x3,y3)
D(x,3x)=(x4,y4)
(x4,y4)=(x1+x3-x2,y1+y3-y2)
(x,3x)=(6+4-(-3),3+(-2)-5)
(x,3x)=(10+3,3-2-5)
(x,3x)=(13,-6)
Therefore,x=13
If three vertices are given in a quadrilateral then the fourth vertex is (x1+x3-x2,y1+y3-y2).
Let,
A(6,3)=(x1,y1)
B(-3,5)=(x2,y2)
C(4,-2)=(x3,y3)
D(x,3x)=(x4,y4)
(x4,y4)=(x1+x3-x2,y1+y3-y2)
(x,3x)=(6+4-(-3),3+(-2)-5)
(x,3x)=(10+3,3-2-5)
(x,3x)=(13,-6)
Therefore,x=13
I also don't know the correct answer.If you know the answer tell to me.
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