Question

IF FREQUENCY F VELOCITY V AND DENSITY D ARE CONSIDERED AS FUNDAMENTAL QUANTITIES. FIND THE DIMENSIONS OF MOMENTUM? ​

Answer 1

Answer:

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Answer 2

Answer:

Dimensions of momentum = [F⁻³V⁴D]

Explanation:

Momentum P = mass x velocity

                      = kg x m/s

                      = $\frac{kg}{m^{3} }$ x $m^{3}$ x $\frac{m}{s}$ x $\frac{s^{3} }{s^{3} }$

                      = $\frac{kg}{m^{3} }$ x $\frac{m^{4} }{s^{4} }$ x $\frac{1}{[\frac{1}{s^{3]} } }$

                      = density x velocity⁴ /frquency³

                      = [DV⁴F⁻³]

∴ Dimensions of momentum = [F⁻³V⁴D]