If frist term is 15 and sum of 10th term is 35 then 10th term ?
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Step-by-step explanation:
nth term = a+(n-1)d
First term = a = 15
Sum of n terms = n/2{2a+(n-1)d}
Sum of 10 terms = 10/2 {2(15)+(10-1)d} = 35
= 5{30+9d} = 35
= 150 + 45d = 35
= 150-35 = -45d
= 115 = -45d
= d = -115/45
d = -23/9
10th term = a+(10-1)d
= 15 + 9d
= 15 + 9(-23/9)
= 15 - 23
= -8
10th term = -8
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