Math, asked by tilakredij1818, 1 year ago

If from any point on the common chord of two intersecting circles, tangents be drawn to the circles, prove they are equal.
Please explain with diagram.

Answers

Answered by ABHINAVrAI
5

Answer:

Step-by-step explanation:

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Consider PT be a tangent to the circle from an external point P and a secant to the circle through P intersects the circle at points A and B, then  PT2 = PA × PB .

This property is used to solve the given question.

Let the two circles intersect at points X and Y. XY is the common chord.

Suppose A is a point on the common chord and AM and AN be the tangents drawn from A to the circle.

AM is the tangent and AXY is a secant.

∴ AM2 = AX × AY      …....(1)

AN is the tangent and AXY is a secant.

∴ AN2 = AX × AY     …..........(2)

From (1) and (2), we get

AM2 = AN2

∴ AM = AN

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Attachments:

tilakredij1818: Thanks for the diagram Bro.
tilakredij1818: Now I can solve myself, only the need was of diagram.
tilakredij1818: Can you give a name to this property.
ABHINAVrAI: This question is based on the theorem that lengths of tangents drawn from an external point to a circle are equal.
Anonymous: Thanks for following me
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