Question

if FX is equal to x cube minus 2 X square + 3 x minus 5 find the value of f minus one​

Answer 1

Answer:

hey frnd here is your answer

Step-by-step explanation:

f(x)=x³-2x²+3x-5 and we have to find f(-1)=?.

so just put x= -1 in f(x).

• f(x)=x³-2x²+3x-5

• f(-1)= (-1)³-2(-1)²+3(-1)-5

• f(-1)= -1+2-3-5

• f(-1)= -7.

so your final answer is-

If f(x)= x³-2x²+3x-5 then f(-1)= -7.

I hope you get your answer

thnx for asking

plzz mark as brainlist..

Answer 2

Answer:

Required value of f(-1) is -11.

Step-by-step explanation:

Given, f(x) is equal to x cube minus 2 X square + 3 x minus 5

In Mathematical form,

$f(x) = {x}^{3} - 2 {x}^{2} + 3x - 5$

This is a problem of Algebra.

f(x) is a function.Here we want to find value of f(-1).

We are putting x= -1 in f(x)

Then

$f( - 1) = {( - 1)}^{3} - 2 {( - 1)}^{2} + 3 \times ( - 1) - 5$

$f( - 1) = - 1 - 2 - 3 - 5 = - 11$

Required value of f(-1) is (-11).

Some important formulas of Algebra,

1.(a + b)² = a² + 2ab + b²

2.(a − b)² = a² − 2ab − b²

3.(a + b)³ = a³ + 3a²b + 3ab² + b³

4.(a - b)³ = a³ - 3a²b + 3ab² - b³

5.(a³ + b³) = (a + b)³ − 3ab(a + b)

6(a³ - b³) = (a -b)³ + 3ab(a - b)

$7.{a}^{2} - {b}^{2} = (a + b)(a - b) \\ 8. {a}^{2} + {b}^{2} = {(a + b)}^{2} - 2ab \\ 9.{a}^{2} + {b}^{2} = {(a - b)}^{2} + 2ab \\ 10.{a}^{3} - {b}^{3} = (a - b)( {a}^{2} + ab + {b}^{2} ) \\ 11.{a}^{3} + {b}^{3} = (a + b)( {a}^{2} - ab + {b}^{2} )$