Question

if G=6.6×10-9 cgs units and radius of earth r=6.36×108 cm, find the density of the earth.​

Answer 1

Hey Dear,

◆ Answer -

d = 5.566 g/cm^3

● Explaination -

Acceleration due to gravity at earth's surface is given by -

g = GM / R²

Rearranging,

M = gR²/G

M = 980 × (6.36×10^8)² / 6.6×10^-8

M = 6×10^27 g

Volume of the earth is calculated as -

V = 4/3 πR^3

V = 4/3 × 3.142 × (6.36×10^8)^3

V = 1.078×10^27 cm^3

Density of the earth is calculated as -

d = M / V

d = 6×10^27 / 1.078×10^27

d = 5.566 g/cm^3

Therefore, density of the earth is approximately 5.566 g/cm^3.

Thanks dear...