if G be the gravitational constant, F be the acceleration and T be the speed Find the dimensions of force?
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Answer:
Dimension of G=M
−1
L
3
T
−2
[c]=[LT
−1
]
[g]=[LT
−2
]
[p]=[ML
−1
T
−2
]
Equate dimensions
[M
−1
L
3
T
−2
]=[LT
−1
]
α
[LT
−2
]
β
[ML
−1
T
−2
]
γ
−1=γ
3=α+β−γ
α+β=2
And, −2=−α−2β−2γ
α+2β=4
Solving (1) and (2) we get,
α=0,β=2
∴Dimension=c
0
g
2
p
−1
I hope it is a he is helpful to you and your
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