Question

Simplify the following expressions: a) arccos(0) , arcsin(-1) , arctan(-1) b) sin(arcsin(-1/2)) , arccos(cos(π/2)) , arccos(cos(-π/2)) c) cos(arcsin(-1/2)) , arcsin(sin(π/3)) , arcsin(tan(3π/4)) d) arccos(tan(7π/4)) ,​

Answer 1

Answer:

search-icon-header

Search for questions & chapters

search-icon-image

Class 12

>>Maths

>>Inverse Trigonometric Functions

>>Inverse Trigonometric Functions

>>Calculate. arctan 1 + arccos ( -

Question

Bookmark

Calculate.

arctan 1+arccos(−

2

1

)+arcsin(−

2

1

)=?

Medium

Solution

verified

Verified by Toppr

arctan1+arccos(−

2

1

)+arcsin(−

2

1

)

=π/4+π−π/3−π/6=

12

3π+12π−4π−2π

=

12

3π

=

4

3π

solution

expand

Solve any question of Inverse Trigonometric Functions with:-