Question

If g is the acceleration due to gravity.The quantity 1/2gt^2 has the dimensions of ​

Answer 1

Answer:

g = acceleration due to gravity

$g = [L {T}^{2} ] \:$

t = time

t = [T]

For ½ g t²

Dimensions will be

$g {t}^{2} = [L {T}^{2} ] \times [{T}^{2} ] \: \\ g {t}^{2} = [L {T}^{4} ]$

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