If G1 , G2 are two G.M’s between a and b then show that G1G2 = ab.
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Answer:
Step-by-step explanation:
We haveG1 and G2 as two geometric means between b and c i.e.
b,G1,G2,c are in G.P.
c = b {(r)}^{4 - 1} \\ c = {br}^{3} \\
r \: = { (\frac{c}{b} )}^{ \frac{1}{3} }
G1 = br = b.(c/b)^1/3
=> G1^3 = b^3 (c/b) = b^2c
G2 = br^2 = b (c/b)^2/3
=> G2^3 = b^3(c^2/b^2) = bc^2
Hope it helps u
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