Question

If grapes are 92% water and raisins are 20% water by weight, then how much did a quantity of raisins, which currently weighs 10 pounds, weigh when all the raisins were grapes? (assume that the only difference between their raisin-weight and their grape-weight is water that evaporated during their transformation.)

Answer 1

Answer:100 pounds

Step-by-step explanation:

as we know, the weight of actual content of grapes/raisins is same in both cases. the difference in amount of water is responsible in different weights of grapes and rasins.

so, this was the thing to understand, now lets get to the solution.

the actual content/matter in rasins----->80%

the actual content in grapes------->8%

actual content in 10 pounds of raisins=80% of 10pounds= 8 pounds

As i said above, actual content will remain same in both the cases, then the actual content will be 8 pounds in grapes also.

so, let the weight of grapes be x

8% of x= 8 pounds

8/100 *x = 8

x = 100 pounds