Question

If h(x)=2x³+(6a²-10)x²+(6a+2)x-14a-2 is exactly divisible by x-1 but not by x+1, find the value of a

Answer 1

x-1=0

x=1

putting this in. equation we get

2+6a^2-10+6a+2-14a-2=0

6a^2-8a-8=0

3a^2-4a-4=0

3a^2'-6a+4a-4=0

3a(a-2)+2(a-2)=0

(3a+2)(a-2)=0

a=2,-2/3

Answer 2

Answer:

a = -2/3,2

this is the answer