if h(x)=3x,g(x)=x+2,f(x)=x²-1,are real functions such that hog of exists ,then (ho(gof))(2)=
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given that h(x)=3x , g(x)=x+2 , f(x)=x²-1
let find (gof)(x)=(x²-1)+2 =x²+1
⇒ (gof)(x)=x²+1
then f(gof)(x)=3(x²+1)
⇒=3x²+3
f(gof)(2)=3(2²+3)
=3(4+3)
=3(7)
=21
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