Question

If HCf(12,16)is written in the form 6m-8, then m is equal to

Answer 1

Answer:

The value of m = 2

Step-by-step explanation:

Given,

The HCF of 12 and 16 is of the form 6m-8

To find,

The value of 'm'

Solution:

To find the HCF of 12 and 16

The prime factorization of 12 = 2×2×3

The prime factorization of 16 = 2×2×2×2

The common factors are 2,2

The highest common factor is 4

The HCF of 12 and 16 = 4

Since it is given that the HCF of 12 and 16 is of the form 6m-8 we have

6m-8 = 4

6m = 4+8 = 12

m = $\frac{12}{6} = 2$

The value of m = 2

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Answer 2

Answer:

The value of m is 2.

Step-by-step explanation:

According to the question,

Given:-

The HCF(12, 16) is written in the form 6m - 8.

To find:-

The value of m.

The factors of the number 12 are:

1, 2, 3, 4, 6, and 12

The factors of the number 16 are:

1, 2, 4, 8, and 16

Observe that the number 4 divides both 12 and 16.

And 4 is the greatest common factor of both the numbers 12 and 16.

Thus,

HCF(12, 16) = 4

Since it is given that HCF of 12 and 16 is written in the form 6m - 8, i.e.,

HCF(12, 16) = 6m - 8

                4 = 6m - 8

          4 + 8 = 6m

               12 = 6m

                2 = m

Therefore, the value of m = 2.

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