Question

If HCF(120,225)=15 then n LCM of 120 and 225 is

Answer 1

Given:-

➜HCF(120&225)=15

$\rule{200}{1}$

To Find:-

✪The LCM of 120&225?

$\rule{200}{1}$

AnsWer:-

☞LCM(120&225)=1800

$\rule{200}{1}$

★Using The Formula★

↝HCF×LCM=Product of Numbers

▼Putting the Values▼

↝15×LCM=120×225

♦Shifting 15 from LHS to RHS♦

↝LCM=$\frac{\cancel{120} \times 225}{\cancel{15}}$

↝LCM=8×225

☞LCM=1800

––––––OR––––––

•Using Factorization Method•

↝5 |120,225

↝2 |24,45

↝2 |12,45

↝2 |6,45

↝3 |3,45

↝5 |1,15

↝3 |1,3

↝1 |1,1

•LCM(120&225)=5×2×2×2×3×5×3×1=1800

$\rule{200}{2}$

Answer 2

___________________________

$\huge\tt{GIVEN:}$

• HCF of 120 & 225 is 15

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$\huge\tt{TO~FIND:}$

• LCM of 120 & 225

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$\huge\tt{</strong><strong>SOLU</strong><strong>TION</strong><strong>:}$

↪Product of Numbers = HCF×LCM

↪120×225 = 15 × LCM

↪LCM = 120 × 225 / 15

↪LCM = 8 × 225

↪LCM = 1800

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