Question

If HCF (225‚60)=225×5-10x‚ then find the value of x.

Answer 1

find the HCF,

a= bq +r
225 = 60*3 +45
60 = 45*1 +15
45 = 15*3 +0

soq when remainder 0 =HCF
=15//

HCF = 225*5 - 10x
15 = 225*5 - 10x
15 = 1125 - 10x
15 - 1125 = -10x
-1110 = -10x

negative sign on both sides get cancelled,

1110 = 10x
x = 1110/10
x=111


hope it helps!!!!

Answer 2

HI there

By Euclid's Division Algorithm :-

a = bq + r

225 > 60

225 = 60 x 3 +45

60 = 45 x 1 + 15

45 = 15 x 3 + 0

H.C.F = 15

Given :-

HCF = 225 × 5 - 10x


15 = 225 × 5 - 10x

15 = 225 x 5 - 10x

15 = 1125 - 10x

15 - 1125 = -10x

-1110 = -10x

x = -1110 / -10

x = 111