If HCF (225‚60)=225×5-10x‚ then find the value of x.
Answers
Answered by
168
Solution :-
H.C.F. of 225 and 60 = (225*5) - 10x
First of all we have to compute the highest common factor of 225 and 60 to solve this question.
H.C.F. Of 225 and 60
3 | 225, 60
|_______________
5 | 75, 20
|_______________
| 15. 4
|
H.C.F. = 3*5
= 15
H.C.F. of 225 and 60 is 15
Now, according to the question.
H.C.F. of 225 and 60 = (225*5) - 10x
15 = (225*5) - 10x
15 = 1125 - 10x
15 - 1125 = - 10x
- 1110 = - 10x
Negative signs are cancelled.
x = 1110/10
x = 111
Hence, the value of x is 111.
Answer.
H.C.F. of 225 and 60 = (225*5) - 10x
First of all we have to compute the highest common factor of 225 and 60 to solve this question.
H.C.F. Of 225 and 60
3 | 225, 60
|_______________
5 | 75, 20
|_______________
| 15. 4
|
H.C.F. = 3*5
= 15
H.C.F. of 225 and 60 is 15
Now, according to the question.
H.C.F. of 225 and 60 = (225*5) - 10x
15 = (225*5) - 10x
15 = 1125 - 10x
15 - 1125 = - 10x
- 1110 = - 10x
Negative signs are cancelled.
x = 1110/10
x = 111
Hence, the value of x is 111.
Answer.
Answered by
21
First we will take the highest common factor of the numbers that is 225 and 60:
So, 3 l 225, 60
5 l 75,20
l 15,4
Now, HCF : 3×5
= 15
So,acc. to ques.
HCF of 225 and 60= (225×5)-10x
15=(225×5)-10x
15=(1125)-10x
15=1125-10x
15-1125=-10x
-1110=-10x
(Both sign will be canceled)
So,
1110=10x
1110/10=x
111=x
Hence,
The value of x is 111.
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