If HCF (6, a) = 2 and LCM (6, a) = 60 then find a
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HCF =2
LCM=60
LCM×HCF =product of the numbers
60×2 =(6×a)
120 =6×a
120÷6 = a
20 = a
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Answered by
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Answer:
Hey dude your answer is
LCM OF 6 AND A IS 60
AND
HCF OF 6 AND A IS 2
SO,THE VALUE OF A IS CAN'T BE 10 BECAUSE LCM OF 6 AND 10 IS 30.
SO,LET'S TAKE THE VALUE OF A AS 20
BECAUSE 60X2=6A
120=6A
120/6=A
THEREFORE,THE VALUE OF A=20
THEREFORE, LCM OF 6 AND 20 IS 60
AND
THEREFORE,HCF OF 6 AND 20 IS 20
SEE ITS HELP AND THANK YOU
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