If HCF of 408 and 1032 is expressible in the form 1032m – 408 × 5, find m
Answers
Answered by
6
HCF of 408 and 1032 = 24
now atq
24= 1032m-408*5
24=1032m-2040
24+2040=1032m
2064=1032m
2064/1032=m
2=m
hope it helps u
now atq
24= 1032m-408*5
24=1032m-2040
24+2040=1032m
2064=1032m
2064/1032=m
2=m
hope it helps u
JattJawandha007:
thanks nandni
Answered by
2
HCF of 408 and 1032 is 24
now
24 = 1032m - 408×5
24 = 1032m - 2040
2064= 1032m
m =2
now
24 = 1032m - 408×5
24 = 1032m - 2040
2064= 1032m
m =2
Similar questions