IF HCF OF 65 AND 117 IS 65m - 117.FIND THE VALUE OF M
Answers
Answered by
11
write 65 and 117 as product of prime
65 = 5×13
117= 3×3×13
hcf(65,117)=13---(1)
given hcf =65m-117---(2)
(2)=(1)
65m-117=13
65m=13+117
65m=130
m=130/65
m=2
65 = 5×13
117= 3×3×13
hcf(65,117)=13---(1)
given hcf =65m-117---(2)
(2)=(1)
65m-117=13
65m=13+117
65m=130
m=130/65
m=2
Similar questions