If HCF of 65 and 117 is expressible in the form 65n ―117, then find the value of n.
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Answer:
Step-by-step explanation:
HCF(65,117)=13
So 65n-117=HCF(65,117)
65n-117=13
65n=13+117
65n=130
n =130/65
n=2
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