if HCF of 65 and 117 is expressible in the form of 65n- 117 then find the value of n
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Answer:
65 = 13 × 5
117 = 13 × 9
HCF of 65 and 117 is 13
65n - 117 = 13 or 65n = 117+13 = 130 or n = 130/65 = 2
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