Question

If hcf of this 65 and 117 is expressed in the form of 65n 117m then what is the value of m and n

Answer 1

By Euclid's division algorithm 

117 = 65x1 + 52.

65 = 52x1 + 13

52 = 13x4 + 0

Therefore 13 is the HCF (65, 117).

Now work backwards:

13 = 65 + 52x(-1)

13 = 65 + [117 + 65x(-1)]x(-1)

13 = 65x(2) + 117x(-1).

∴ m = 2 and n = -1.

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Answer 2

the answer is the pic.