If HCF of two numbers is 20 and sum of the numbers is 220 then how many pairs of such number exists?
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Step-by-step explanation:
As both the numbers have the highest common factor 12 it clearly means that the both the numbers are the multiples if 12
So let the numbers be 12x and 12y
As given their sum is 84
ATQ,12x+12y=84
12 (x+y)=84
x+y=7
So the number of pairs with 7 as their sum are (1,6),(2,5),(3,4)
That is three pairs
So the numbers are (12,72),(24,60), (36,48)
Hope it helpss
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