Question

If HCF ( X, 14)=6, LCM(X, 14)=28, thenfind the value ofx.
OR
1
Thedecimalrepresentationof
53
willterminateafterhowmanydecimalplaces?
22x 5​

Answer 1

Answer:

Given: HCF (x,14) = 6,LCM (x,14) = 28

Mistake in the given question  

As we know that HCF is always a factor of LCM but in this question 6 is not the factor of  28.

Correct question:

If HCF ( x , 14 ) = 2 and LCM ( x , 14 ) = 28 then find the value of x

To Find : Value of x

Solution:

LCM of two numbers = 28  , HCF of two numbers = 6 and second number = 14

We know that,

LCM x HCF = first number x second number

28 x 2  = x ×  14

First number = ( 28 x 2 ) /14  

First number = 56/14  

First number = 4  

Hence, the value of x is 4.

Step-by-step explanation:

thank you

Answer 2

Answer:

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