If HCF(x,y)= 6 and xy=180, find the LCM(x,y).
Answers
Answered by
1
We know that,
LCM(x, y) × HCF(x, y) = xy
→ LCM(x, y) × 6= 180
→ LCM(x, y) = 180 ÷ 6= 30
→ LCM(x, y) = 30
LCM(x, y) × HCF(x, y) = xy
→ LCM(x, y) × 6= 180
→ LCM(x, y) = 180 ÷ 6= 30
→ LCM(x, y) = 30
Answered by
1
Answer:
Lcm=30
Step-by-step explanation:
xy=180
Hcf=6
priduct of two numbers=hcf*lcm
- let Lcm be m
=→180=6*m
=→6m=180
=→m=180/6
=→30
Lcm=30.
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