Question

if heat
of combustion of Ch4 is
-x kj/ mol.then heat released during
combustion of a 0.16g of CH4, will be​

Answer 1

Combustion of methane :

CH4+2O2⟶CO2+2H2O

Given weight of methane =16g

Molecular weight of methane =16g

No. of moles of methane in 16g of it =mol. wt.given wt.=1616=1 mole

From the reaction,

Amount of water produced by the combustion of 1 mole of methane = 2 moles

weight of 1 mole of water =18g

⇒ weight of 2 moles of water =2×18=36g

Since, the given weight of methane is 16 g, hence the water produced by the combustion of 16 g of methane is 36 g.

Answer 2

Given - Heat of combustion of methane -x kj/mol.

Find - Heat of combustion of 0.16 gram of methane.

Solution - Combustion of methane can be represented as -

CH4 + 2O2 --> CO2 + 2H2O

For this reaction, heat of combustion will be -x kj/mol.

For 0.16 gram methane,

number of moles = weight/Molecular weight.

Number of moles = 0.16/16

Number of moles = 0.1

As, Combustion of 1 mole releases energy = -x

Combustion of 0.1 mole will release energy = -x*0.1

Heat released = -0.1x kJ/mol

Hence, heat released during combustion of 0.16 gram of methane will be -0.1x kJ/mol