If hydrogen and oxygen combine in ratio of 1:8 by mass respectively to form water molecule. Explain how many moles of water will be formed using 10moles of H gas and 5moles of O2 gas?
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Hii There!!!
In the given question ,
Since , Atomic Mass of H2 = 1 × 1 = 2g
and Atomic mass of O2 = 16 g
So,
Mass of hydrogen = 2 × 10 = 20g
∴ No. of moles of hydrogen = 20 moles.
Similarly ,
Mass of oxygen = 16 × 5 = 80g
∴ No. of moles of oxygen = 80 moles
===============================
Now , We know that
80 grams of Oxygen reacts with 10 grams of Hydrogen which will give 80 + 10 = 90 g of water..
So, we will get the following equation =>
H2 + O2 ------> 2H2O
=> 10g + 80g ------> 90g
Also, By using the formula =>
No. of moles = Given mass / Molar mass
=> No. of moles = 90 /18 = 5
Hence, number of moles = 5 moles of water.
_________________________
# ¢' $ #
Hope it helps :)
In the given question ,
Since , Atomic Mass of H2 = 1 × 1 = 2g
and Atomic mass of O2 = 16 g
So,
Mass of hydrogen = 2 × 10 = 20g
∴ No. of moles of hydrogen = 20 moles.
Similarly ,
Mass of oxygen = 16 × 5 = 80g
∴ No. of moles of oxygen = 80 moles
===============================
Now , We know that
80 grams of Oxygen reacts with 10 grams of Hydrogen which will give 80 + 10 = 90 g of water..
So, we will get the following equation =>
H2 + O2 ------> 2H2O
=> 10g + 80g ------> 90g
Also, By using the formula =>
No. of moles = Given mass / Molar mass
=> No. of moles = 90 /18 = 5
Hence, number of moles = 5 moles of water.
_________________________
# ¢' $ #
Hope it helps :)
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