if hypotenuse of right angles triangle is 20cm. the difference between the other lengths of side is 4cm. find the sides.
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Hypotenuse =20. Side 1 = x. Side 2 = y
According to Pythagoras theorem,
(20)2 = (x)2 + (y)2
400=x2 + y2. --1
Now the difference between the sides is 4
That is....x-y=4
x-y=4
x=4+y. ----2
Putting 2 in 1 , we get
400 = (4+y)2 + ( y)2
400=16 +8y +y2+y2
400=16+8y+2 y2
400-16=8y + 2 y2
384=2y2+8y
0=y2+4y-192
0=y2 + 16y -12y -192
0=y(y+16)-12(y+16)
0=(y+16) (y-12)
Y=12cm
X=4+12=16cm
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