Physics, asked by bharatyadav7105, 3 months ago

If hypothetically, radius of earth increases by a factor
of 3, then by what factor its density should change to
keep value of g same? (assume mass unchanged)​

Answers

Answered by Sayantana
13

Answer:

density is inversely proportional to R

Explanation:

if radius of earth increases by factor of 3 then its density will get decrease by the factor of 3 to keep the value of g Same

Attachments:

kookukumari: so is the answer :- 3
Sayantana: yes..
Answered by amitnrw
2

Given : radius of earth increases by a factor of 3

To Find : by what factor its density should change to keep value of g same​

Solution:

g = GM/r²

M = Mass of Earth

r = radius of earth

G = Universal Gravitational constant

Density = Mass /Volume

Density = ρ

Volume = (4/3)πr³

=> ρ = M/ (4/3)πr³

=> M = ρ  (4/3)πr³

g = GM/r²

=>

g = Gρ  (4/3)πr³/r²

=> g =  Gρ  (4/3)πr³/r²

=> g =  Gρ (4/3)πr

=> g =   (4/3)πGρr

g is constant

 (4/3)πG are constant

Hence ρr  should be constant

=> if radius of earth increases by a factor of 3

then ρ has to decrease by a factor of 3

Density should be 1/3rd

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