If hypothetically, radius of earth increases by a factor
of 3, then by what factor its density should change to
keep value of g same? (assume mass unchanged)
Answers
Answer:
density is inversely proportional to R
Explanation:
if radius of earth increases by factor of 3 then its density will get decrease by the factor of 3 to keep the value of g Same
Given : radius of earth increases by a factor of 3
To Find : by what factor its density should change to keep value of g same
Solution:
g = GM/r²
M = Mass of Earth
r = radius of earth
G = Universal Gravitational constant
Density = Mass /Volume
Density = ρ
Volume = (4/3)πr³
=> ρ = M/ (4/3)πr³
=> M = ρ (4/3)πr³
g = GM/r²
=>
g = Gρ (4/3)πr³/r²
=> g = Gρ (4/3)πr³/r²
=> g = Gρ (4/3)πr
=> g = (4/3)πGρr
g is constant
(4/3)πG are constant
Hence ρr should be constant
=> if radius of earth increases by a factor of 3
then ρ has to decrease by a factor of 3
Density should be 1/3rd
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