if i cap , jcap and kcap represents unit vectors along the x , y ,and z axis then find the angle between i cap + jcap +k cap and i cap +j cap
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We know from the dot product rule that ,
A.B = |A| |B| cosФ
So,
cosФ = (A.B) /(|A| |B|)
cosФ = (( i + j + k).(j +k))/ (√3 ×√2)
cosФ = 2/(√6)
So,
Ф = cos inverse of (2 /√6)
This will be the required angle between the vectors
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