if i grams bullet acquires speed of 120 metre per second in a gun with barrel length 2.0 the average force exerted on the bullet is
Answers
Answered by
0
Answer:
Conservation of linear momentum gives,
m
1
v
1
+m
2
v
2
=0
m
1
v
1
=−m
2
v
2
v
1
=
m
1
−m
2
v
2
Given, m
1
=10g=(
1000
10
)kg,
m
2
=1 kg,
v
2
=−5m/s
∴v
1
=
10/1000
+1×5
or v
1
=500m/s.
Similar questions