Question

. If I have 6.2 litres of gas in a piston at a pressure of 2 atm and compress the gas until its volume is 4.1 L, what will the new pressure inside the piston be? (Give answer upto two places of decimal)

Answer 1

Answer:-

Given:

Initial Volume (V1) = 6.2 L

Initial Pressure (P1) = 2 atm.

Final Volume (V2) = 4.1 L

We know that,

Boyle's law of gases states that at constant temperature the pressure of a gas is inversely proportional to it's Volume.

$\implies\sf\large{ \: P \: \: \alpha \: \: \frac{1}{V} }$

→ PV = k (Constant)

$\sf \implies \: P _{1}V_{1} = P _{2}V _{2}$

→ (6.2)(2) = (P2)(4.1)

→ (12.4)/(4.1) = P2

→ P2 = 3.0 = 3 atm. (Approx)

Hence, the pressure of the gas is increased to 3 atm.