Physics, asked by rsrinu9912, 10 months ago

if i^,j^,k,are unit vectors along x,y,z directions then
i^×i^,
j^×j^,
k^×k^,
i^×j^,
j^×k^,
k^×i^
pls answer fast please

Answers

Answered by sharwankumarjakhar
0

Answer:

Chiraglalwani

13.07.2018

Physics

Secondary School

+5 pts

Answered

If i , j, and k represent unit vectors along the x , y and z - axis respectively , then the angle theta between the vectors i + j +k and i + j is equal to

2

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QHM avatar

Angle between 2 vectors is given cosα=i+j+k*i+j/√3√2=2/√6.

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Therefore α=cos inverse 2/√6.

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QHMGenius

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LidaralbanyVirtuoso

Answer:

The angle between the vectors is \theta=cos^{-1}\dfrac{2}{\sqrt{6}}.

Explanation:

Given that,

Let us consider the vector A= i+j+k and vector B = i+j.

If i , j, and k represent unit vectors along the x , y and z - axis respectively.

The angle between the vectors is

cos\theta = \dfrac{\vec{A}\cdot\vec{B}}{|A|\cdot|B|}

cos\theta=\dfrac{(i+j+k)\cdot(i+j)}{\sqrt{3}\cdot\sqrt{2}}

cos\theta=\dfrac{2}{\sqrt{6}}

\theta=cos^{-1}\dfrac{2}{\sqrt{6}}

Hence, The angle between the vectors is \theta=cos^{-1}\dfrac{2}{\sqrt{6}}.

Explanation:

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