if i^,j^,k,are unit vectors along x,y,z directions then
i^×i^,
j^×j^,
k^×k^,
i^×j^,
j^×k^,
k^×i^
pls answer fast please
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Answer:
Chiraglalwani
13.07.2018
Physics
Secondary School
+5 pts
Answered
If i , j, and k represent unit vectors along the x , y and z - axis respectively , then the angle theta between the vectors i + j +k and i + j is equal to
2
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QHM avatar
Angle between 2 vectors is given cosα=i+j+k*i+j/√3√2=2/√6.
QHM avatar
Therefore α=cos inverse 2/√6.
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LidaralbanyVirtuoso
Answer:
The angle between the vectors is \theta=cos^{-1}\dfrac{2}{\sqrt{6}}.
Explanation:
Given that,
Let us consider the vector A= i+j+k and vector B = i+j.
If i , j, and k represent unit vectors along the x , y and z - axis respectively.
The angle between the vectors is
cos\theta = \dfrac{\vec{A}\cdot\vec{B}}{|A|\cdot|B|}
cos\theta=\dfrac{(i+j+k)\cdot(i+j)}{\sqrt{3}\cdot\sqrt{2}}
cos\theta=\dfrac{2}{\sqrt{6}}
\theta=cos^{-1}\dfrac{2}{\sqrt{6}}
Hence, The angle between the vectors is \theta=cos^{-1}\dfrac{2}{\sqrt{6}}.
Explanation:
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