Question

If i leave my house at 6:52 am and run 1 mile at an easy pace (8:15 per mile), then 3 miles at tempo (7:12 per mile) and 1 mile at easy pace again, what time do i get home for breakfast?

Answer 1

Answer:

Finish time was 7:30

start_time_hr = 6 + 52 / 60.0

easy_pace_hr = (8 + 15 / 60.0 ) / 60.0

tempo_pace_hr = (7 + 12 / 60.0) / 60.0

running_time_hr = 2 * easy_pace_hr + 3 * tempo_pace_hr

breakfast_hr = start_time_hr + running_time_hr

breakfast_min = (breakfast_hr-int(breakfast_hr))*60

breakfast_sec= (breakfast_min-int(breakfast_min))*60

Finish time was 7:30

Answer 2

Answer:

7:50

Step-by-step explanation:

leaving_house_hr=6+52/60

easy_pase_hr=(8+15/60)/60

temp_hr=(7+12/60)/60

breakfasttime=leaving_house_hr+easy_pase_hr*2+3*temp_hr