If I root of the quadrilateral equation 2x2+kx-6=0 is 2. Find the value of k and also find the other root.
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Hey
The given equation is :-
2x² + kx - 6 = 0
one root is 2 .
So ,
putting the value of x ,
2 ( 2 ) ² + k ( 2 ) - 6 = 0
=> 8 - 6 + 2k = 0
=> 2 + 2k = 0
=> 2k = -2
=> k = -1
thanks :)
The given equation is :-
2x² + kx - 6 = 0
one root is 2 .
So ,
putting the value of x ,
2 ( 2 ) ² + k ( 2 ) - 6 = 0
=> 8 - 6 + 2k = 0
=> 2 + 2k = 0
=> 2k = -2
=> k = -1
thanks :)
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