Question

if if length of the rectangle is 12cm and the breadth is one less than half of the length then the perimeter of the rectangle us​


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Answer 1

$\sf Given \begin{cases} & \sf{Length_{\:(rectangle)} = \bf{12\:cm}} \\ & \sf{Breadth_{\:(rectangle)} = \dfrac{Length}{2} - 1 = 6 - 1 = \bf{5\:cm}} \end{cases}$

To find: Perimeter of Rectangle?

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⋆ Diagram

$\setlength{\unitlength}{0.9cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 12 cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 5 cm}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

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$\dag\;{\underline{\frak{As\;we\;know\;that,}}}$

⋆ Perimeter of Rectangle is given by,

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$\star\;{\boxed{\sf{\pink{Perimeter_{\;(rectangle)} = 2(length + breadth)}}}}$

Here,

Length, l = 12 cm

Breadth, b = 5 cm

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$\dag\;{\underline{\frak{Putting\:values\:in\:formula,}}}$

$:\implies\sf Perimeter_{\;(rectangle)} = 2(l + b)\\ \\ \\:\implies\sf Perimeter_{\;(rectangle)} = 2(12 + 5)\\ \\ \\:\implies\sf Perimeter_{\;(rectangle)} = 2 \times 17\\ \\ \\ :\implies{\underline{\boxed{\frak{\purple{Perimeter_{\;(rectangle)} = 34\:cm}}}}}\;\bigstar$

$\therefore\:{\underline{\sf{Perimeter\:of\:rectangle\:is\:{\textsf{\textbf{34\:cm}}}.}}}$

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$\qquad\boxed{\underline{\underline{\pink{\bigstar \: \bf\:Formulas\:related\:to\:rectangle\:\bigstar}}}}$

$\sf Area\:of\:rectangle = \bf{length \times breadth}$

$\sf Perimeter\:of\:rectangle = \bf{2(length + breadth)}$

$\sf Diagonal\:of\:rectangle = \bf{\sqrt{(length)^2 + (breadth)^2}}$

Answer 2

Answer:

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Step-by-step explanation:

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$14()) - \times 34$

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