If in a ap 24th term is twice the 10th term proove that 36th term is twce the 16th term ..
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a24=2a10
a+23d=(a+9d)2
a+23d=2a+18d
a-5d=0
a=5d
a+35d=a36
40d=a36
a16=a+15d
a16=20d
(a16)2=a36
a+23d=(a+9d)2
a+23d=2a+18d
a-5d=0
a=5d
a+35d=a36
40d=a36
a16=a+15d
a16=20d
(a16)2=a36
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