Question

If in a given reaction no3- is reduced to nh4+, the mass of no3- absorbing one mole of electrons would be

Answer 1

Dear Student,

● Answer -

W = 7.75 g

● Explaination -

Reduction of NO3- to NH4+ takes place according to following reaction.

NO3- + 10H+ + 8e- → NH4+ + 3H2O

From this, we can see that 8 mole of e- are required for conversion of one NO3- to NH4+.

Hence, for 1 mol of e- will be absorbed by 1/8 mol NO3-.

Mass of 1/8 mol NO3- is given by -

W = n × M

W = 1/8 × 62

W = 7.75 g

Therefore, 7.75 g NO3- will absorb one mole of e-.

Hope I was useful..