If in a group of dogs and crow, the number of heads is 25 and the number of feet is 70
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Let the number of dogs be 'x' and number of crow be 'y'
Then, according to the question
x + y = 25 -----------------(1)
4x + 2y = 70
⇒ 2x + y = 35 ------------(2)
Solving eq(1) and eq(2), we get
x = 10
putting x = 10 in eq(1), we get y = 15
∴ number of dogs(x) = 10 & number of crows(y) = 15
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