if in a triangle ABC, BC=CA and Angle A= 40° which is longer BC or AB
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Answers
Answer:
AB
Step-by-step explanation:
In ABC
BC=CA
➡ Angle A = angle B (by isosceles triangle property)
Therefore AB is the longest side
Given data : In a triangle ABC, BC = CA and Angle A = 40⁰.
To find : Which is longer BC or AB
Solution : Here, we know, a triangle in which two sides are equal is called an isosceles triangle.
Now,a/c to given data,
➜ ∠ A = 40⁰ ----{1}
The sum of the internal angles of all triangles is always 180.
Hence,
➜ ∠ A + ∠ B + ∠ C = 180⁰
Two sides of a triangle are equal, then the angles opposite to those sides are also equal.
Hence, a/c to figure;
∠ A = ∠ B
Hence, the measure of ∠ A and ∠ B is 40⁰
Now,
➜ ∠ A + ∠ B + ∠ C = 180⁰
➜ 40 + 40 + ∠ C = 180⁰
➜ 80 + ∠ C = 180⁰
➜ ∠ C = 180 - 80
➜ ∠ C = 100
Hence, ∠ C = 100⁰ ----{2}
From {1} and {2}
Measure of ∠ A and ∠ B is less than ∠ C.
Here, we know, side opposite to greater angle is larger and side opposite to smaller angle is smaller.
∴ side AB > side BC
Answer : Hence, the side AB is larger than the side BC.